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Kovid Goyal 2021-01-18 16:31:09 +05:30
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docs/keyboard-protocol.rst
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@ -151,7 +151,7 @@ Modifiers are encoded as a bit field with::
In the escape code, the modifier value is encoded as a decimal number which is In the escape code, the modifier value is encoded as a decimal number which is
``1 + actual modifiers``. So to represent :kbd:`shift` only, the value would be ``1 + ``1 + actual modifiers``. So to represent :kbd:`shift` only, the value would be ``1 +
1 = 2``, to represent :kbd:`ctrl+shift` the value would be ``1 + 0b101 = 5`` 1 = 2``, to represent :kbd:`ctrl+shift` the value would be ``1 + 0b101 = 6``
and so on. If the modifier field is not present in the escape code, its default and so on. If the modifier field is not present in the escape code, its default
value is ``1`` which means no modifiers. value is ``1`` which means no modifiers.