Fix exception when getting function name for debug_keyboard action dispatch
Fixes #1401
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aed504efdc
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@ -34,8 +34,8 @@ from .rgb import Color, color_from_int
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from .session import create_session
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from .tabs import SpecialWindow, SpecialWindowInstance, TabManager
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from .utils import (
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get_editor, get_primary_selection, is_path_in_temp_dir, log_error,
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open_url, parse_address_spec, remove_socket_file, safe_print,
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func_name, get_editor, get_primary_selection, is_path_in_temp_dir,
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log_error, open_url, parse_address_spec, remove_socket_file, safe_print,
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set_primary_selection, single_instance, startup_notification_handler
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)
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@ -577,7 +577,7 @@ class Boss:
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f = getattr(self, key_action.func, None)
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if f is not None:
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if self.args.debug_keyboard:
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print('Keypress matched action:', f.__name__)
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print('Keypress matched action:', func_name(f))
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passthrough = f(*key_action.args)
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if passthrough is not True:
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return True
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@ -592,7 +592,7 @@ class Boss:
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if f is not None:
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passthrough = f(*key_action.args)
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if self.args.debug_keyboard:
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print('Keypress matched action:', f.__name__)
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print('Keypress matched action:', func_name(f))
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if passthrough is not True:
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return True
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return False
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@ -449,3 +449,11 @@ def is_path_in_temp_dir(path):
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if q and path.startswith(q):
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return True
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return False
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def func_name(f):
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if hasattr(f, '__name__'):
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return f.__name__
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if hasattr(f, 'func') and hasattr(f.func, '__name__'):
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return f.func.__name__
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return str(f)
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