get rid of the who -m ssh session test
I dont like executing a binary in a fast startup script. Lets see if there are a lot of sessions in the wild that dont use the SSH_TTY env var
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@ -157,9 +157,6 @@ _ksi_main() {
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if [[ "${_ksi_prompt[title]}" == "y" ]]; then
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if [[ -n "$SSH_TTY$SSH2_TTY" ]]; then
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_ksi_prompt[hostname_prefix]="\h: ";
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elif [[ -n "$(builtin command -v who)" ]]; then
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# OpenSSH's sshd creates entries in utmp for every login so use those
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[[ "$(builtin command who -m 2> /dev/null)" =~ "\([a-fA-F.:0-9]+\)$" ]] && _ksi_prompt[hostname_prefix]="\h: ";
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fi
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# see https://www.gnu.org/software/bash/manual/html_node/Controlling-the-Prompt.html#Controlling-the-Prompt
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# we use suffix here because some distros add title setting to their bashrc files by default
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@ -235,9 +235,6 @@ _ksi_deferred_init() {
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builtin local is_ssh_session="n"
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if [[ -n "$SSH_TTY$SSH2_TTY" ]]; then
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is_ssh_session="y";
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elif [[ -n "$(builtin command -v who)" ]]; then
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# OpenSSH's sshd creates entries in utmp for every login so use those
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[[ "$(builtin command who -m 2> /dev/null)" =~ "\([a-fA-F.:0-9]+\)$" ]] && is_ssh_session="y";
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fi
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if [[ "$is_ssh_session" == "y" ]]; then
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