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Dont list all releases when publishing, instead just query the API for the existing release directly

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Kovid Goyal 2021-09-29 10:52:51 +05:30
parent cb1858ecc8
commit 35dee0c46e
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GPG Key ID: 06BC317B515ACE7C
1 changed files with 7 additions and 16 deletions
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21
publish.py
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@ -17,7 +17,7 @@ import sys
import tempfile
import time
from contextlib import contextmanager, suppress
from typing import IO, Any, Dict, Generator, Iterable, List, Optional, cast
from typing import IO, Any, Dict, Generator, Iterable, Optional, cast
import requests
@ -257,9 +257,8 @@ class GitHub(Base): # {{{
)
def __call__(self) -> None:
releases = self.releases()
# self.clean_older_releases(releases)
release = self.create_release(releases)
release = self.create_release()
upload_url = release['upload_url'].partition('{')[0]
asset_url = self.url_base + 'assets/{}'
existing_assets = self.existing_assets(release['id'])
@ -333,20 +332,12 @@ class GitHub(Base): # {{{
self.fail(r, 'Failed to get assets for release')
return {asset['name']: asset['id'] for asset in r.json()}
def releases(self) -> List[Dict[str, Any]]:
url = self.API + 'repos/%s/%s/releases' % (self.username, self.reponame
)
r = self.requests.get(url)
if r.status_code != 200:
self.fail(r, 'Failed to list releases')
return list(r.json())
def create_release(self, releases: Iterable[Dict[str, str]]) -> Dict[str, Any]:
def create_release(self) -> Dict[str, Any]:
' Create a release on GitHub or if it already exists, return the existing release '
for release in releases:
# Check for existing release
if release['tag_name'] == self.current_tag_name:
return release
r = self.requests.get(self.API + f'/repos/{self.username}/{self.reponame}/releases/tags/{self.current_tag_name}')
if r.status_code == 200:
return dict(r.json())
if self.is_nightly:
raise SystemExit('No existing nightly release found on GitHub')
url = self.API + 'repos/%s/%s/releases' % (self.username, self.reponame)